2[2q+1]=3[q-2]

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Solution for 2[2q+1]=3[q-2] equation:


Simplifying
2[2q + 1] = 3[q + -2]

Reorder the terms:
2[1 + 2q] = 3[q + -2]
[1 * 2 + 2q * 2] = 3[q + -2]
[2 + 4q] = 3[q + -2]

Reorder the terms:
2 + 4q = 3[-2 + q]
2 + 4q = [-2 * 3 + q * 3]
2 + 4q = [-6 + 3q]

Solving
2 + 4q = -6 + 3q

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-3q' to each side of the equation.
2 + 4q + -3q = -6 + 3q + -3q

Combine like terms: 4q + -3q = 1q
2 + 1q = -6 + 3q + -3q

Combine like terms: 3q + -3q = 0
2 + 1q = -6 + 0
2 + 1q = -6

Add '-2' to each side of the equation.
2 + -2 + 1q = -6 + -2

Combine like terms: 2 + -2 = 0
0 + 1q = -6 + -2
1q = -6 + -2

Combine like terms: -6 + -2 = -8
1q = -8

Divide each side by '1'.
q = -8

Simplifying
q = -8

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